Q.Point P is any point inside a circle centered at O. If the radius of the circle is 5 cm and OP = 3 cm, then find the minimum length of the chord passing through point P.

The chord passing through point P with minimum length will be perpendicular to OP. \(\therefore\) OP ⊥ AB In triangle OAP: \(AP^2 = OA^2 - OP^2\) i.e., \(AP^2 = 5^2 - 3^2 = 25 - 9\) i.e., \(AP^2 = 16\) i.e., \(AP = 4\) \(\therefore\) AB = 2 × AP = 2 × 4 cm = 8 cm
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