Q.y is equal to the sum of two variables—one is directly proportional to x, and the other is inversely proportional to x. When x = 1, y = -1; and when x = 3, y = 5. Determine the relationship between x and y.

Let \(p\) and \(q\) be two variables, where \(p\) is directly proportional to \(x\) and \(q\) is inversely proportional to \(x\). So, \[ y = p + q \] and \[ p \propto x \Rightarrow p = k_1 x \quad [k_1 \text{ is a non-zero constant}] \] \[ q \propto \frac{1}{x} \Rightarrow q = \frac{k_2}{x} \quad [k_2 \text{ is a non-zero constant}] \] Therefore, \[ y = k_1 x + \frac{k_2}{x} \quad \text{—— (i)} \] Substituting \(x = 1\), \(y = -1\) into equation (i): \[ -1 = k_1 + k_2 \Rightarrow k_1 + k_2 = -1 \quad \text{—— (ii)} \] Substituting \(x = 3\), \(y = 5\) into equation (i): \[ 5 = 3k_1 + \frac{k_2}{3} \Rightarrow 15 = 9k_1 + k_2 \quad \text{—— (iii)} \] Subtracting equation (ii) from equation (iii): \[ (9k_1 + k_2) - (k_1 + k_2) = 15 + 1 \Rightarrow 8k_1 = 16 \Rightarrow k_1 = 2 \] Putting \(k_1 = 2\) into equation (ii): \[ 2 + k_2 = -1 \Rightarrow k_2 = -3 \] Substituting the values of \(k_1\) and \(k_2\) into equation (i): \[ y = 2x - \frac{3}{x} \] ∴ The relationship between \(x\) and \(y\) is: \[ y = 2x - \frac{3}{x} \]
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