Q.If \(x ∝ y\) and \(y ∝ z\), then prove that \((x^2 + y^2 + z^2) ∝ (xy + yz + zx)\).

Let \(x ∝ y\), i.e., \(x = k_1y\) [where \(k_1\) is a non-zero constant] And \(y ∝ z\), i.e., \(y = k_2z\) [where \(k_2\) is a non-zero constant] Now consider: \(\cfrac{x^2 + y^2 + z^2}{xy + yz + zx}\) \(= \cfrac{k_1^2y^2 + k_2^2z^2 + z^2}{k_1y \cdot k_2z + k_2z \cdot z + z \cdot k_1y}\) \(= \cfrac{k_1^2k_2^2z^2 + k_2^2z^2 + z^2}{k_1k_2^2z^2 + k_2z^2 + k_1k_2z^2}\) \(= \cfrac{z^2(k_1^2k_2^2 + k_2^2 + 1)}{z^2(k_1k_2^2 + k_2 + k_1k_2)}\) \(= \cfrac{(k_1^2k_2^2 + k_2^2 + 1)}{(k_1k_2^2 + k_2 + k_1k_2)}\) \(=\) constant \(\therefore\) \((x^2 + y^2 + z^2) ∝ (xy + yz + zx)\) (Proved)
Similar Questions