Answer: D
\[ \sin\theta \times \tan\theta + \cos\theta \\ = \sin\theta \times \frac{\sin\theta}{\cos\theta} + \cos\theta \\ = \frac{\sin^2\theta}{\cos\theta} + \cos\theta \\ = \frac{\sin^2\theta + \cos^2\theta}{\cos\theta} \\ = \frac{1}{\cos\theta} \\ = \sec\theta \]
\[ \sin\theta \times \tan\theta + \cos\theta \\ = \sin\theta \times \frac{\sin\theta}{\cos\theta} + \cos\theta \\ = \frac{\sin^2\theta}{\cos\theta} + \cos\theta \\ = \frac{\sin^2\theta + \cos^2\theta}{\cos\theta} \\ = \frac{1}{\cos\theta} \\ = \sec\theta \]