Q.The distance from the center of a circle to an external point is 13 cm. The length of the tangent from that point to the circle is 12 cm. The radius of the circle is— (a) 25 cm (b) 1 cm (c) 5 cm (d) \(\cfrac{13}{12}\) cm
Answer: C
OB⊥AB
∴ OB\(^2\)+12\(^2\)=OA\(^2\)
or OB\(^2\)+144=13\(^2\)
or OB\(^2\)=169-144=25
or OB=√25=5
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