Two circles intersect at points P and Q. PA and PB are the diameters of the respective circles. We need to prove that points A, Q, and B lie on a straight line. **Construction:** Join points P and Q. **Proof:** Since PA is the diameter of one circle, ∠PQA is an angle in a semicircle. ∴ ∠PQA = 90° Similarly, PB is the diameter of the other circle, so ∠PQB is also an angle in a semicircle. ∴ ∠PQB = 90° ∴ ∠AQB = ∠PQA + ∠PQB = 90° + 90° = 180° ∴ AQB forms a straight line. ∴ A, Q, and B are collinear. (Proved)