Answer: D
Let the heights be \(h_1\) and \(h_2\), and the radii of the bases be \(4r\) and \(5r\), respectively.
∴ \(\cfrac{1}{3} π(4r)^2 h_1 : \cfrac{1}{3} π(5r)^2 h_2 = 1:4\)
or, \(16r^2 h_1 : 25r^2 h_2 = 1:4\)
or, \(\cfrac{16h_1}{25h_2} = \cfrac{1}{4}\)
or, \(\cfrac{h_1}{h_2} = \cfrac{25}{64}\)
Thus, \(h_1 : h_2 = 25:64\).
Let the heights be \(h_1\) and \(h_2\), and the radii of the bases be \(4r\) and \(5r\), respectively.
∴ \(\cfrac{1}{3} π(4r)^2 h_1 : \cfrac{1}{3} π(5r)^2 h_2 = 1:4\)
or, \(16r^2 h_1 : 25r^2 h_2 = 1:4\)
or, \(\cfrac{16h_1}{25h_2} = \cfrac{1}{4}\)
or, \(\cfrac{h_1}{h_2} = \cfrac{25}{64}\)
Thus, \(h_1 : h_2 = 25:64\).