Q.If \( \tan \theta \cos 60° = \cfrac{√3}{2} \), find the value of \(\sin(\theta - 15°)\) (a) \(\cfrac{1}{√2}\) (b) 1 (c) √2 (d) 0
Answer: A
\(\tan \theta \cos 60° = \cfrac{√3}{2}\)
or, \(\tan \theta \times \cfrac{1}{2} = \cfrac{√3}{2}\)
or, \(\tan \theta = √3 = \tan 60°\)
or, \(\theta = 60°\)

\(\therefore\) \(\sin(\theta - 15°) = \sin(60° - 15°)\)
\( = \sin 45° = \cfrac{1}{√2}\).
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