Q.\(\sin(2x-20°)=\cos(2y+20°)\)
বা, \(\sin(2x-20°)=\sin[90^o-(2y+20°)]\)
বা, \(2x-20°= 90^o-(2y+20°)\)
বা, \(2x-20°= 90^o-2y-20°\)
বা, \(2x+2y= 90^o-20°+20°\)
বা, \(2(x+y)= 90^o\)
বা, \((x+y)= 45^o\)

\(\therefore \tan(x+y)=\tan 45^o=1\) (Answer)
- translate in english

\(\sin(2x - 20^\circ) = \cos(2y + 20^\circ)\) Or, \(\sin(2x - 20^\circ) = \sin[90^\circ - (2y + 20^\circ)]\) Or, \(2x - 20^\circ = 90^\circ - (2y + 20^\circ)\) Or, \(2x - 20^\circ = 90^\circ - 2y - 20^\circ\) Or, \(2x + 2y = 90^\circ - 20^\circ + 20^\circ\) Or, \(2(x + y) = 90^\circ\) Or, \(x + y = 45^\circ\) \(\therefore \tan(x + y) = \tan 45^\circ = 1\) (Answer)
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