Q.What is the simplest value of \(\cfrac{\sqrt{8} + \sqrt{12}}{\sqrt{32} + \sqrt{48}}\)? (a) \(\cfrac{1}{3}\) (b) \(\cfrac{1}{4}\) (c) \(\cfrac{1}{2}\) (d) \(\cfrac{1}{\sqrt2}\)
Answer: C
\(\cfrac{\sqrt{8} + \sqrt{12}}{\sqrt{32} + \sqrt{48}}\) \(= \cfrac{2\sqrt{2} + 2\sqrt{3}}{4\sqrt{2} + 4\sqrt{3}}\) \(= \cfrac{2(\sqrt{2} + \sqrt{3})}{4(\sqrt{2} + \sqrt{3})}\) \(= \cfrac{2}{4} = \cfrac{1}{2}\)
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