Q.If \(\frac{\sin \theta + \cos \theta}{\sin \theta - \cos \theta} = 5\), then what is the value of \(\tan \theta\)?

\[ \frac{\sin \theta + \cos \theta}{\sin \theta - \cos \theta} = 5 \] Or, \[ \frac{(\sin \theta + \cos \theta) + (\sin \theta - \cos \theta)}{(\sin \theta + \cos \theta) - (\sin \theta - \cos \theta)} = \frac{5 + 1}{5 - 1} \] [Using the method of addition and subtraction] So, \[ \frac{\sin \theta + \cos \theta + \sin \theta - \cos \theta}{\sin \theta + \cos \theta - \sin \theta + \cos \theta} = \frac{6}{4} \] \[ \Rightarrow \frac{2\sin \theta}{2\cos \theta} = \frac{3}{2} \Rightarrow \frac{\sin \theta}{\cos \theta} = \frac{3}{2} \Rightarrow \tan \theta = \frac{3}{2} \] (Answer)
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