Q.If the median of the following data is 28.5 and the total frequency is 60, determine the values of x and y.
Class Interval0-1010-2020-30
Frequency5x20
30-4040-5050-60
15y5

The frequency distribution table for the class is:
Class BoundariesFrequencyCumulative Frequency (less than type)
0-1055
10-20\(x\)5+\(x\)
20-302025+\(x\)
30-401540+\(x\)
40-50\(y\)40+\(x+y\)
50-60545+\(x+y=n\)
Given \( n = 60 \), By condition, \( 45 + x + y = 60 \) or, \( x + y = 15 ----(i) \) Also, since the median is \( 28.5 \), The median class is \( (20-30) \). The median formula: \[ = l + \left[\cfrac{\cfrac{n}{2}-cf}{f}\right]×h \] where, \( l = 20, n = 60, \) \( cf = 5 + x, f = 20, h = 10 \) \[ = 20 + \left[\cfrac{30-(5+x)}{20}\right]×10 \] \[ = 20 + \cfrac{25-x}{20}×10 \] \[ = 20 + \cfrac{25-x}{2} \] By condition: \[ 20+ \cfrac{25-x}{2} = 28.5 \] \[ \cfrac{25-x}{2} = 8.5 \] \[ 25 - x = 17 \] \[ -x = -8 \] \[ x = 8 \] Substituting \( x \) in equation (i): \[ 8 + y = 15 \] \[ y = 7 \] Thus, the required values: \( x = 8, y = 7 \).
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