Q.If \(\sin^4 \theta + \sin^2 \theta = 1\), then prove that \(\tan^4 \theta - \tan^2 \theta = 1\).

Given: \[ \sin^4 \theta + \sin^2 \theta = 1 \Rightarrow \sin^4 \theta = 1 - \sin^2 \theta \Rightarrow \sin^4 \theta = \cos^2 \theta \] Now consider: \[ \tan^4 \theta - \tan^2 \theta = \frac{\sin^4 \theta}{\cos^4 \theta} - \tan^2 \theta = \frac{\cos^2 \theta}{\cos^4 \theta} - \tan^2 \theta \quad [\text{Since } \sin^4 \theta = \cos^2 \theta] = \frac{1}{\cos^2 \theta} - \tan^2 \theta = \sec^2 \theta - \tan^2 \theta = 1 \] ( proved)
Similar Questions