Q.If the average of \(n\) natural numbers is \(\cfrac{n+8}{4}\), then what is the value of \(n\)? (a) 4 (b) 6 (c) 8 (d) 0
Answer: B

The average of \(n\) natural numbers is
\(\cfrac{\sum n}{n} = \cfrac{\cfrac{n(n+1)}{2}}{n}\) \(= \cfrac{n+1}{2}\)
\(\therefore \cfrac{n+1}{2} = \cfrac{n+8}{4}\) or, \(4n + 4 = 2n + 16\) or, \(4n - 2n = 16 - 4\) or, \(2n = 12\) or, \(n = 6\)

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