Q.If the volume of a cube is \(V\) cubic centimeters, the total surface area is \(S\) square centimeters, and the length of the diagonal is \(d\) centimeters, then prove that \(Sd = 6\sqrt{3}V\).
Let each edge of the cube be \(a\) units.
\(\therefore\) Volume of the cube, \(V = a^3\)
And total surface area, \(S = 6a^2\)
And diagonal, \(d = \sqrt{3}a\)
\(\therefore Sd = 6a^2 \times \sqrt{3}a = 6\sqrt{3}a^3 = 6\sqrt{3}V\)
(Proved)