Q.If the volume of a cube is \(V\) cubic centimeters, the total surface area is \(S\) square centimeters, and the length of the diagonal is \(d\) centimeters, then prove that \(Sd = 6\sqrt{3}V\).

Let each edge of the cube be \(a\) units. \(\therefore\) Volume of the cube, \(V = a^3\) And total surface area, \(S = 6a^2\) And diagonal, \(d = \sqrt{3}a\) \(\therefore Sd = 6a^2 \times \sqrt{3}a = 6\sqrt{3}a^3 = 6\sqrt{3}V\) (Proved)
Similar Questions