Q.If \(0^\circ < θ < 90^\circ\), then \( \sin θ > \sin^2 θ \).

The statement is true.

If \(0^\circ < θ < 90^\circ\), then the value of \( \sin θ \) will always lie between 0 and 1. Therefore, in this case, \( \sin θ > \sin^2 θ \).
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