Let the first positive even number be \(x\). Therefore, the next consecutive positive even number is \(x + 2\). According to the question: \[ x^2 + (x + 2)^2 = 340 \Rightarrow x^2 + x^2 + 4x + 4 - 340 = 0 \Rightarrow 2x^2 + 4x - 336 = 0 \Rightarrow x^2 + 2x - 168 = 0 \] Now factorizing: \[ x^2 + 14x - 12x - 168 = 0 \Rightarrow x(x + 14) - 12(x + 14) = 0 \Rightarrow (x + 14)(x - 12) = 0 \] So, either \(x + 14 = 0\) ⇒ \(x = -14\) (Not acceptable since it's negative) Or, \(x - 12 = 0\) ⇒ \(x = 12\) Therefore, the two numbers are 12 and 14.