Q.The sum of the squares of two consecutive positive even numbers is 340. Find the two numbers.

Let the first positive even number be \(x\). Therefore, the next consecutive positive even number is \(x + 2\). According to the question: \[ x^2 + (x + 2)^2 = 340 \Rightarrow x^2 + x^2 + 4x + 4 - 340 = 0 \Rightarrow 2x^2 + 4x - 336 = 0 \Rightarrow x^2 + 2x - 168 = 0 \] Now factorizing: \[ x^2 + 14x - 12x - 168 = 0 \Rightarrow x(x + 14) - 12(x + 14) = 0 \Rightarrow (x + 14)(x - 12) = 0 \] So, either \(x + 14 = 0\) ⇒ \(x = -14\) (Not acceptable since it's negative) Or, \(x - 12 = 0\) ⇒ \(x = 12\) Therefore, the two numbers are 12 and 14.
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