Q.If \(\sin \theta + \cos \theta = \sqrt{2}\), then what is the value of \(\theta\)? (a) \(\cfrac{\pi}{2}\) (b) \(\cfrac{\pi}{3}\) (c) \(\pi\) (d) \(\cfrac{\pi}{4}\)
Answer: D
\(\sin \theta + \cos \theta = \sqrt{2}\)
Or, \((\sin \theta + \cos \theta)^2 = (\sqrt{2})^2\)
Or, \(\sin^2 \theta + \cos^2 \theta + 2\sin \theta \cos \theta = 2\)
Or, \(1 + 2\sin \theta \cos \theta = 2\)
Or, \(2\sin \theta \cos \theta = 2 - 1\)
Or, \(2\sin \theta \cos \theta = 1\)
Or, \(\sin 2\theta = \sin \frac{\pi}{2}\)
Or, \(2\theta = \frac{\pi}{2}\)
Or, \(\theta = \frac{\pi}{4}\)
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