In a right-angled triangle, the sum of the two acute angles is \(90^\circ\). Let the smaller angle be \(x^\circ\). ∴ The other angle is \((x + 72)^\circ\). So, \(x + x + 72 = 90\) i.e. \(2x + 72 = 90\) i.e. \(2x = 18\) ⇒ \(x = 9\) ∴ The measures of the two angles are \(9^\circ\) and \((72 + 9)^\circ = 81^\circ\) We know that \(180^\circ = \pi\) radians ∴ \(9^\circ = \frac{\pi \times 9}{180} = \frac{\pi}{20}\) radians and \(81^\circ = \frac{\pi \times 81}{180} = \frac{9\pi}{20}\) radians ∴ The measures of the two angles in radians are \(\frac{\pi}{20}\) radians and \(\frac{9\pi}{20}\) radians.