Q.If one root of the quadratic equation \(ax^2 + abcx + bc = 0\) (\(a \ne 0\)) is the reciprocal of the other, then — (a) abc=1 (b) b=ac (c) bc=1 (d) a=bc
Answer: D
Let one root be \(\alpha\) Then the other root is \(\frac{1}{\alpha}\) \(\therefore\) Product of the roots \[ \alpha \times \frac{1}{\alpha} = \frac{bc}{a} \] So, \[ 1 = \frac{bc}{a} \] Hence, \[ bc = a \]
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