Answer: C
Let’s assume the principal amount \((p)= x\) rupees
\(\therefore\) Interest amount \((I)= \cfrac{5x}{16}\) rupees
Time \((t)=6\cfrac{1}{4} \) years \(=\cfrac{25}{4} \) years
Rate of interest \((r)= \%\)
\(\therefore\) Rate of interest \((r)=\cfrac{100\times I}{pt} \%\)
Let’s assume the principal amount \((p)= x\) rupees
\(\therefore\) Interest amount \((I)= \cfrac{5x}{16}\) rupees
Time \((t)=6\cfrac{1}{4} \) years \(=\cfrac{25}{4} \) years
Rate of interest \((r)= \%\)
\(\therefore\) Rate of interest \((r)=\cfrac{100\times I}{pt} \%\)
\(=\cfrac{100\times \cfrac{5x}{16}}{x\times \cfrac{25}{4}} \%\)
\(=\cfrac{\cancel{100}\cancel4\times 5\cancel x\times \cancel4}{\cancel x\times \cancel{25} \times \cancel{16}\cancel4} \%\)
\(=5 \%\)