Q.O is the circumcenter of triangle ABC. If \(\angle\)BAC = 85° and \(\angle\)BCA = 70°, then what is the measure of \(\angle\)OAC? (a) \(65^o\) (b) \(42\cfrac{1}{2}^o\) (c) \(50^o\) (d) \(25^o\)
Answer: A
In triangle ABC, \(\angle\)ABC = 180° − (\(\angle\)BAC + \(\angle\)BCA) = 180° − (85° + 70°) = 25° ∴ Central angle \(\angle\)AOC = 2 × \(\angle\)ABC = 2 × 25° = 50° Now, in triangle AOC, AO = OC ∴ \(\angle\)OAC = \(\angle\)OCA = \(\frac{1}{2}\)(180° − 50°) = 65° ∴ \(\angle\)OAC = 65° (Answer)
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