Q.If \((a+b) : \sqrt{ab} = 2:1\), then the value of \(a:b\) will be 1:1.


\(\cfrac{(a+b)}{\sqrt{ab}} = \cfrac{2}{1}\)
Or, \(\cfrac{(a+b)^2}{ab} = 4\)
Or, \((a+b)^2 = 4ab\)
Or, \((a+b)^2 - 4ab = 0\)
Or, \((a-b)^2 = 0\)
Or, \(a - b = 0\)
Or, \(a = b\)
Or, \(\cfrac{a}{b} = 1\)
\(\therefore a:b = 1:1\)
(Proved)
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