Answer: D
Let the radius of the second sphere be \(r\) units. \(\therefore\) The radius of the first sphere = \(2r\) units. So, Surface area of the first sphere = \(4\pi(2r)^2\) Volume of the second sphere = \(\frac{4}{3}\pi r^3\) Equating the two: \[ 4\pi(2r)^2 = \frac{4}{3}\pi r^3 \] \[ 16\pi r^2 = \frac{4}{3}\pi r^3 \] \[ 4 = \frac{r}{3} \] \[ r = 12 \] \(\therefore\) Radius of the first sphere = \(2r = 2 \times 12 = 24\) units.
Let the radius of the second sphere be \(r\) units. \(\therefore\) The radius of the first sphere = \(2r\) units. So, Surface area of the first sphere = \(4\pi(2r)^2\) Volume of the second sphere = \(\frac{4}{3}\pi r^3\) Equating the two: \[ 4\pi(2r)^2 = \frac{4}{3}\pi r^3 \] \[ 16\pi r^2 = \frac{4}{3}\pi r^3 \] \[ 4 = \frac{r}{3} \] \[ r = 12 \] \(\therefore\) Radius of the first sphere = \(2r = 2 \times 12 = 24\) units.