Q.The length of a rectangular field is \(\frac{3}{2}\) times its breadth. If the length is reduced by 1200 cm and the breadth is increased by 1200 cm, the field becomes a square. Find the area of the field.

Let the side length of the square field be \(x\) cm. \(\therefore\) The length of the rectangular field is \((x + 1200)\) cm and the breadth is \((x - 1200)\) cm. According to the question, \((x + 1200) = \frac{3}{2} \times (x - 1200)\) Or, \(2x + 2400 = 3x - 3600\) Or, \(2x - 3x = -3600 - 2400\) Or, \(-x = -6000\) Or, \(x = 6000\) \(\therefore\) The length of the rectangular field is \((6000 + 1200)\) cm = \(7200\) cm and the breadth is \((6000 - 1200)\) cm = \(4800\) cm \(\therefore\) Area of the field = length \(\times\) breadth = \((7200 \times 4800)\) sq cm = \(34,560,000\) sq cm.
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