Q.If the sides of a triangle are in the ratio \(\sqrt{7} : \sqrt{3} : 2\), then what type of triangle is it? (a) right angle. (b) equilateral (c) isosceles (d) obtuse-angle
Answer: A
In this case, \((\sqrt{3})^2 + 2^2 = (\sqrt{7})^2\) ∴ A triangle with side ratios \(\sqrt{7} : \sqrt{3} : 2\) is a right-angled triangle.
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