Q.Prove that: \(1^\circ < 1^c\)

\(180^\circ = \pi^c\) Therefore, \(1^\circ = \left(\frac{\pi}{180}\right)^c = \left(\frac{22}{7 \times 180}\right)^c\) So, \(1^\circ < 1^c\) \(\Big[\because \frac{22}{7 \times 180} < 1\Big]\) ∴ \(1^\circ < 1^c\) (Proved)
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