Q.A hollow iron pipe has an inner radius of 3 feet and an outer radius of 4 feet. Its length is 20 feet. If the weight of 1 cubic foot of iron is 10 kilograms, what is the weight of the pipe? (a) 4400 kg (b) 4000 kg (c) 4040 kg (d) None of the above
Answer: A
Volume of the pipe = \[ \pi(4^2 - 3^2) \times 20 \text{ cubic feet} = \frac{22}{7} \times 7 \times 20 \text{ cubic feet} = 440 \text{ cubic feet} \] ∴ Weight of the pipe = \[ 440 \times 10 \text{ kilograms} = 4400 \text{ kilograms} \]
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