Answer: A
Volume of the pipe = \[ \pi(4^2 - 3^2) \times 20 \text{ cubic feet} = \frac{22}{7} \times 7 \times 20 \text{ cubic feet} = 440 \text{ cubic feet} \] ∴ Weight of the pipe = \[ 440 \times 10 \text{ kilograms} = 4400 \text{ kilograms} \]
Volume of the pipe = \[ \pi(4^2 - 3^2) \times 20 \text{ cubic feet} = \frac{22}{7} \times 7 \times 20 \text{ cubic feet} = 440 \text{ cubic feet} \] ∴ Weight of the pipe = \[ 440 \times 10 \text{ kilograms} = 4400 \text{ kilograms} \]