Q.If \( \tan \theta = \cfrac{8}{15} \), find the value of \( \sin \theta \).

Given: \[ \tan \theta = \cfrac{8}{15} \Rightarrow \tan^2 \theta = \left(\cfrac{8}{15}\right)^2 = \cfrac{64}{225} \Rightarrow \cot^2 \theta = \cfrac{225}{64} \Rightarrow 1 + \cot^2 \theta = 1 + \cfrac{225}{64} = \cfrac{289}{64} \Rightarrow \cosec^2 \theta = \cfrac{289}{64} \Rightarrow \cosec \theta = \sqrt{\cfrac{289}{64}} = \cfrac{17}{8} \] \[ \therefore\ \sin \theta = \cfrac{1}{\cosec \theta} = \cfrac{8}{17} \]
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