Answer: B
The central angle \(\angle BOC\) and the inscribed angle \(\angle BAC\) subtend the same arc BC. \(\therefore \angle BAC = \frac{1}{2} \angle BOC = \frac{1}{2} \times 120^\circ = 60^\circ\)
The central angle \(\angle BOC\) and the inscribed angle \(\angle BAC\) subtend the same arc BC. \(\therefore \angle BAC = \frac{1}{2} \angle BOC = \frac{1}{2} \times 120^\circ = 60^\circ\)