Answer: A
In triangles PAD and PCB: \(\angle\)PAD = \(\angle\)PCB [opposite exterior angles] \(\angle\)PDA = \(\angle\)PBC [opposite exterior angles] ∴ Triangles PAD and PCB are similar. ∴ \(\cfrac{PA}{PC} = \cfrac{PD}{PB}\) ∴ \(PA \cdot PB = PC \cdot PD\)
In triangles PAD and PCB: \(\angle\)PAD = \(\angle\)PCB [opposite exterior angles] \(\angle\)PDA = \(\angle\)PBC [opposite exterior angles] ∴ Triangles PAD and PCB are similar. ∴ \(\cfrac{PA}{PC} = \cfrac{PD}{PB}\) ∴ \(PA \cdot PB = PC \cdot PD\)