Given: \[ \sin 23^\circ = p \] Then, \[ \sin^2 23^\circ = p^2 \] \[ \Rightarrow 1 - \sin^2 23^\circ = 1 - p^2 \] \[ \Rightarrow \cos^2 23^\circ = 1 - p^2 \] \[ \Rightarrow \cos 23^\circ = \sqrt{1 - p^2} \] \[ \Rightarrow \cos(90^\circ - 67^\circ) = \sqrt{1 - p^2} \] \[ \Rightarrow \sin 67^\circ = \sqrt{1 - p^2} \quad \text{(Answer)} \]