Q."AB is a diameter of a circle with center O. P is any point on the circumference. If ∠ POA = 120°, then what is the measure of ∠ PBO?" (a) 90\(^o\) (b) 60\(^o\) (c) 75\(^o\) (d) None of the above
Answer: B
\(\angle\)POA = 120° ∴ In triangle BOP, \(\angle\)PBO + \(\angle\)BPO = exterior angle \(\angle\)POA So, \(2\angle\)PBO = 120° [∵ OB = OP = radius of the circle ∴ \(\angle\)PBO = \(\angle\)BPO] Therefore, \(\angle\)PBO = 60°
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