Answer: B
Let \( 2a = 3b = 4c = k \).
Thus, \( a = \frac{k}{2} \), \( b = \frac{k}{3} \), and \( c = \frac{k}{4} \).
Therefore, \( a : b : c = \frac{k}{2} : \frac{k}{3} : \frac{k}{4} = \frac{1}{2} : \frac{1}{3} : \frac{1}{4} \).
Which simplifies to \( 6 : 4 : 3 \).
Let \( 2a = 3b = 4c = k \).
Thus, \( a = \frac{k}{2} \), \( b = \frac{k}{3} \), and \( c = \frac{k}{4} \).
Therefore, \( a : b : c = \frac{k}{2} : \frac{k}{3} : \frac{k}{4} = \frac{1}{2} : \frac{1}{3} : \frac{1}{4} \).
Which simplifies to \( 6 : 4 : 3 \).