Given: Let ∠ACB and ∠ADB be any two angles subtended by arc AB in a circle with center O. To Prove: All angles subtended by the same arc ACDB are equal. Construction: Join OA and OB. Proof: ∠AOB is the central angle subtended by arc AB, and ∠ACB and ∠ADB are angles on the circumference. ∠AOB = 2∠ACB ∠AOB = 2∠ADB So, 2∠ACB = 2∠ADB ∴ ∠ACB = ∠ADB