Q.G is the centroid of equilateral triangle ABC; if AB = 10 cm, then what is the length of AG? (a) \(10\sqrt3\) cm (b) \(\cfrac{10}{3}\) cm (c) \(10\) cm (d) \(\cfrac{10\sqrt3}{3}\) cm
Answer: D
Height of equilateral triangle ABC = \((\cfrac{\sqrt{3}}{2} \times 10)\) cm = \(5\sqrt{3}\) cm. \(\therefore\) Length of AG = \(5\sqrt{3} \times \cfrac{2}{3}\) cm = \(\cfrac{10\sqrt{3}}{3}\) cm.
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