Answer: D
Height of equilateral triangle ABC = \((\cfrac{\sqrt{3}}{2} \times 10)\) cm = \(5\sqrt{3}\) cm. \(\therefore\) Length of AG = \(5\sqrt{3} \times \cfrac{2}{3}\) cm = \(\cfrac{10\sqrt{3}}{3}\) cm.
Height of equilateral triangle ABC = \((\cfrac{\sqrt{3}}{2} \times 10)\) cm = \(5\sqrt{3}\) cm. \(\therefore\) Length of AG = \(5\sqrt{3} \times \cfrac{2}{3}\) cm = \(\cfrac{10\sqrt{3}}{3}\) cm.