Answer: A
Here’s the English translation of your solution: In triangle \( \triangle ABC \): \[ AC^2 = AB^2 + BC^2 \] Or, \[ AC^2 = AB^2 + 3AB^2 \quad [\text{Because } BC = \sqrt{3} \times AB] \] So, \[ AC^2 = 4AB^2 \] Therefore, \[ AC = 2AB \] Hence, \[ \sin C = \frac{AB}{AC} = \frac{AB}{2AB} = \frac{1}{2} \]
Here’s the English translation of your solution: In triangle \( \triangle ABC \): \[ AC^2 = AB^2 + BC^2 \] Or, \[ AC^2 = AB^2 + 3AB^2 \quad [\text{Because } BC = \sqrt{3} \times AB] \] So, \[ AC^2 = 4AB^2 \] Therefore, \[ AC = 2AB \] Hence, \[ \sin C = \frac{AB}{AC} = \frac{AB}{2AB} = \frac{1}{2} \]