Q.In triangle \( \triangle ABC \), if \( \angle B \) is a right angle and \( BC = \sqrt{3} \times AB \), then what is the value of \( \sin C \)? (a) \(\frac{1}{2}\) (b) \(\frac{1}{\sqrt2}\) (c) \(\frac{\sqrt3}{2}\) (d) 1
Answer: A
Here’s the English translation of your solution: In triangle \( \triangle ABC \): \[ AC^2 = AB^2 + BC^2 \] Or, \[ AC^2 = AB^2 + 3AB^2 \quad [\text{Because } BC = \sqrt{3} \times AB] \] So, \[ AC^2 = 4AB^2 \] Therefore, \[ AC = 2AB \] Hence, \[ \sin C = \frac{AB}{AC} = \frac{AB}{2AB} = \frac{1}{2} \]
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