Since the roots of the equation are equal, \(\therefore\) the discriminant is zero. So, \((c - a)^2 - 4(b - c)(a - b) = 0\) Expanding: \(c^2 + a^2 - 2ac - 4(ab - b^2 - ac + bc) = 0\) Simplifying: \(c^2 + a^2 - 2ac - 4ab + 4b^2 + 4ac - 4bc = 0\) Combining like terms: \(a^2 + c^2 + 4b^2 + 2ac - 4ab - 4bc = 0\) This simplifies to: \((a + c - 2b)^2 = 0\) ⇒ \(a + c - 2b = 0\) ⇒ \(a + c = 2b\)Proved.