Answer: A
Let’s assume the principal amount \((p)=x\) rupees
Time \( (t)=30\) years
Interest \((I)=(3x-x)\) rupees =\(2x\) rupees
∴ Rate of interest \((r)=\cfrac{100×I}{pt}\)
\(=\cfrac{100×2x}{x×30} \%=\cfrac{20}{3}\%=6\cfrac{2}{3}\%\)
Let’s assume the principal amount \((p)=x\) rupees
Time \( (t)=30\) years
Interest \((I)=(3x-x)\) rupees =\(2x\) rupees
∴ Rate of interest \((r)=\cfrac{100×I}{pt}\)
\(=\cfrac{100×2x}{x×30} \%=\cfrac{20}{3}\%=6\cfrac{2}{3}\%\)