Q.If \(\sin(2x + y) = \cos(4x - y)\), find the value of \(\tan 3x\).

\(\sin(2x + y) = \cos(4x - y)\) i.e., \(\sin(2x + y) = \sin[90^\circ - (4x - y)]\) i.e., \(2x + y = 90^\circ - (4x - y)\) i.e., \(2x + y = 90^\circ - 4x + y\) i.e., \(2x + 4x = 90^\circ + y - y\) i.e., \(6x = 90^\circ\) i.e., \(x = 15^\circ\) i.e., \(3x = 45^\circ\) \(\therefore \tan 3x = \tan 45^\circ = 1\) (Answer)
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