In the right-angled triangle \(\triangle\)ABC: \[ AC^2 = AB^2 + BC^2 \Rightarrow AC^2 = 5^2 + 12^2 = 25 + 144 = 169 \Rightarrow AC = \sqrt{169} = 13 \] In a right-angled triangle, the radius of the circumcircle is half the length of the hypotenuse. \[ \therefore \text{Radius of the circumcircle of } \triangle ABC = \frac{13}{2} \text{ cm} = 6.5 cm \]