Q.In a circle centered at O, chords AB and CD are equidistant from the center. If ∠AOB = 60° and CD = 6 cm, then what is the radius of the circle?
In triangle OAB, OA = OB = radius of the circle
∴ ∠OAB = ∠OBA
And ∠AOB = 60° (given)
Also, AB = CD = 6 cm (given)
∴ ∠OAB = ∠OBA = ∠OAB = 60°
That means triangle OAB is equilateral
Where OA = OB = AB = 6 cm
∴ Radius of the circle = 6 cm