Q.In a circle centered at O, chords AB and CD are equidistant from the center. If ∠AOB = 60° and CD = 6 cm, then what is the radius of the circle?

In triangle OAB, OA = OB = radius of the circle ∴ ∠OAB = ∠OBA And ∠AOB = 60° (given) Also, AB = CD = 6 cm (given) ∴ ∠OAB = ∠OBA = ∠OAB = 60° That means triangle OAB is equilateral Where OA = OB = AB = 6 cm ∴ Radius of the circle = 6 cm
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