Q.The radius of a circle centered at point O is 5 cm. Point P is located 13 cm away from point O. PQ and PR are two tangents drawn from point P to the circle. What is the area of quadrilateral PQOR?
OQ\(^2\) + PQ\(^2\) = OP\(^2\)
i.e., 5\(^2\) + PQ\(^2\) = 13\(^2\)
i.e., PQ\(^2\) = 169 − 25
i.e., PQ = 12
Area of ∆OPQ = \(\cfrac{1}{2}\) × 12 × 5 sq. cm
= 30 sq. cm
∴ Area of PQOR = 2 × ∆OPQ
= 2 × 30 sq. cm = 60 sq. cm