Q.The radius of a circle centered at point O is 5 cm. Point P is located 13 cm away from point O. PQ and PR are two tangents drawn from point P to the circle. What is the area of quadrilateral PQOR?

OQ\(^2\) + PQ\(^2\) = OP\(^2\) i.e., 5\(^2\) + PQ\(^2\) = 13\(^2\) i.e., PQ\(^2\) = 169 − 25 i.e., PQ = 12 Area of ∆OPQ = \(\cfrac{1}{2}\) × 12 × 5 sq. cm                       = 30 sq. cm ∴ Area of PQOR = 2 × ∆OPQ               = 2 × 30 sq. cm = 60 sq. cm
Similar Questions