Let the principal be ₹\(x\). \[ \therefore 2x = x\left(1 + \frac{r}{100}\right)^8 \Rightarrow \left(1 + \frac{r}{100}\right)^8 = 2 \] Now, suppose the principal becomes 4 times in \(n\) years. \[ \therefore 4x = x\left(1 + \frac{r}{100}\right)^n \Rightarrow \left(1 + \frac{r}{100}\right)^n = 4 = 2^2 \Rightarrow \left(1 + \frac{r}{100}\right)^n = \left(1 + \frac{r}{100}\right)^{16} \] \[ \therefore n = 16 \] Therefore, the principal will become 4 times in 16 years.