Answer: B
In triangles PAD and PCB: \(\angle\)PAD = \(\angle\)PCB [opposite exterior angles] \(\angle\)PDA = \(\angle\)PBC [opposite exterior angles] ∴ Triangles PAD and PCB are similar. ∴ \(\cfrac{PA}{PC} = \cfrac{PD}{PB}\) i.e., \(\cfrac{6}{PC} = \cfrac{8}{2}\) ⇒ \(PC = 1.5\) ∴ PC = 1.5 cm.
In triangles PAD and PCB: \(\angle\)PAD = \(\angle\)PCB [opposite exterior angles] \(\angle\)PDA = \(\angle\)PBC [opposite exterior angles] ∴ Triangles PAD and PCB are similar. ∴ \(\cfrac{PA}{PC} = \cfrac{PD}{PB}\) i.e., \(\cfrac{6}{PC} = \cfrac{8}{2}\) ⇒ \(PC = 1.5\) ∴ PC = 1.5 cm.