Answer: C
The ratio of the curved surface areas = \(2\pi r_1 h_1 : 2\pi r_2 h_2\)
\(= \cfrac{r_1 h_1}{r_2 h_2}\)
\(= \cfrac{r_1}{r_2} \times \cfrac{h_1}{h_2} \)
\(= \cfrac{2}{3} \times \cfrac{5}{3} = 10 : 9\)
The ratio of the curved surface areas = \(2\pi r_1 h_1 : 2\pi r_2 h_2\)
\(= \cfrac{r_1 h_1}{r_2 h_2}\)
\(= \cfrac{r_1}{r_2} \times \cfrac{h_1}{h_2} \)
\(= \cfrac{2}{3} \times \cfrac{5}{3} = 10 : 9\)