Answer: C
The two angles adjacent to the base of the cone are equal, and each measures 60°. \[ \therefore \] The height of the cone will be equal to the height of an equilateral triangle with a side length of 12 cm. \[ \therefore \] Height of the cone = \( \frac{\sqrt{3}}{2} \times 12 \) cm = \( 6\sqrt{3} \) cm.
The two angles adjacent to the base of the cone are equal, and each measures 60°. \[ \therefore \] The height of the cone will be equal to the height of an equilateral triangle with a side length of 12 cm. \[ \therefore \] Height of the cone = \( \frac{\sqrt{3}}{2} \times 12 \) cm = \( 6\sqrt{3} \) cm.