Answer: C
\(n = x\) years, \(r = x\%\), \(I = x\) rupees
\(\therefore p = \cfrac{100x}{x \times x}\) rupees = \(\cfrac{100}{x}\) rupees.
\(n = x\) years, \(r = x\%\), \(I = x\) rupees
\(\therefore p = \cfrac{100x}{x \times x}\) rupees = \(\cfrac{100}{x}\) rupees.