Q.If the median of the following data is 28.5, and the total frequency is 60, determine the values of x and y.
Class Interval0-1010-2020-30
Frequency5x20
30-4040-5050-60
15y5

The frequency distribution table:
Class BoundariesFrequencyCumulative Frequency (Less Than)
0-1055
10-20\(x\)5+\(x\)
20-302025+\(x\)
30-401540+\(x\)
40-50\(y\)40+\(x+y\)
50-60545+\(x+y=n\)
Here, \(n=60\) (Given). By condition, \(45+x+y=60\), or, \(x+y=15----(i)\). Since the median = 28.5, The median class is (20-30). Formula for median: \(=l+\left[\cfrac{\cfrac{n}{2}-cf}{f}\right]×h\) Where: \(l=20\), \(n=60\), \(cf=5+x\), \(f=20\), \(h=10\). \(=20+\left[\cfrac{30-(5+x)}{20}\right]×10\) \(=20+\cfrac{25-x}{20}×10\) \(=20+\cfrac{25-x}{2}\) By condition: \(20+ \cfrac{25-x}{2}=28.5\) or, \(\cfrac{25-x}{2}=8.5\) or, \(25-x=17\) or, \(-x=-8\) or, \(x=8\). Substituting \(x\) in equation (i): \(8+y=15\) or, \(y=7\). âˆī Required values: \(x=8, y=7\).
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