Answer: D
\[ \frac{x}{y} \propto (x + y) \Rightarrow \frac{x}{y} = k_1(x + y) \quad [k_1 \text{ is a non-zero constant}] \quad \text{---(i)} \] and \[ \frac{y}{x} \propto (x - y) \Rightarrow \frac{y}{x} = k_2(x - y) \quad [k_2 \text{ is a non-zero constant}] \quad \text{---(ii)} \] Multiplying equations (i) and (ii), we get: \[ \frac{x}{y} \times \frac{y}{x} = k_1(x + y) \times k_2(x - y) \Rightarrow 1 = k_1k_2(x^2 - y^2) \Rightarrow x^2 - y^2 = \frac{1}{k_1k_2} = \text{constant} \]
\[ \frac{x}{y} \propto (x + y) \Rightarrow \frac{x}{y} = k_1(x + y) \quad [k_1 \text{ is a non-zero constant}] \quad \text{---(i)} \] and \[ \frac{y}{x} \propto (x - y) \Rightarrow \frac{y}{x} = k_2(x - y) \quad [k_2 \text{ is a non-zero constant}] \quad \text{---(ii)} \] Multiplying equations (i) and (ii), we get: \[ \frac{x}{y} \times \frac{y}{x} = k_1(x + y) \times k_2(x - y) \Rightarrow 1 = k_1k_2(x^2 - y^2) \Rightarrow x^2 - y^2 = \frac{1}{k_1k_2} = \text{constant} \]